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X^2+4X^2+8X-3=0
We add all the numbers together, and all the variables
5X^2+8X-3=0
a = 5; b = 8; c = -3;
Δ = b2-4ac
Δ = 82-4·5·(-3)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{31}}{2*5}=\frac{-8-2\sqrt{31}}{10} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{31}}{2*5}=\frac{-8+2\sqrt{31}}{10} $
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